Answer :
The surface area expressed in square feet of a single face of a pile is 1.45 square feet.
Explanation:
The dimensions of the pillar are given as 14 in [tex]\times[/tex] 14 in
(1 feet = 12 inch)
According to the pillar dimensions mentioned in the problem, the length of the pillar should be 15 inches, height by 14 inches and the width by 14 inches.
There will be two surface areas of the concrete pile, one implies side surface area and the other is end surface area.
For calculating the side surface area,
Area of the side surface = 14 in [tex]\times[/tex] 15 in
= [tex]14 in.[/tex] [tex]\times[/tex] [tex]\frac{1 ft.}{12 in.}[/tex]
= 1.16 [tex]\times[/tex] 1.25
= 1.45 square feet.
(In the given question, only a single face is asked so there is no need to find the surface area of the end face.)
The surface area of the side face of the given pile is 1.45 ft². The surface area is the area of all surfaces in a 3D object such as a pillar, ball, etc.
What is surface area?
The surface area is the area of all surfaces in a 3D object such as a pillar, ball, etc.
A pillar has two types of faces, side face and end phase with dimensions 14x14 and 14x15.
The dimentions of the pile,
Length - 14 inches = 1.16 ft
Width - 14 inches = 1.16 ft
height - 15 inches = 1.25 ft.
So, the surface area of a side face will be
As = 1.16 ft x 1.25 ft
As = 1.45 ft²
Therefore, the surface area of the side face of the given pile is 1.45 ft².
Learn more about the Surface area:
https://brainly.com/question/24720806