makadz1645 makadz1645

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Physics

Answered

A pair of oppositely charged parallel plates is separated by 5.38 mm. A potential difference of 623 V exists between the plates. What is the strength of the electric field between the plates? The fundamental charge is 1.602 × 10−19 . Answer in units of V/m.

Answer :

olumidechemeng olumidechemeng

Today at 6:41 AM

Answer:

115799.256V/m

Explanation:

Given V = 623v, d = 5.38mm = 0.00538m

Strength of electric field E = V/d

E = 623/0.00538

= 115799.256V/m

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