Answer :
Answer
given,
vertical speed of the dragon = 6 m/s
height of dragon above ground = 30 m
a) maximum height of the ball.
At the topmost point velocity is equal to zero
Using equation of motion
[tex]v^2 = u^2 + 2 a h[/tex]
[tex]0^2 =6^2 - 2\times 9.8\times h[/tex]
h = 1.84 m
maximum height of the egg above ground
H = 30 + 1.84 = 31.84 m
b) time taken by the ball to reach the ground
[tex]s = ut + \dfrac{1}{2}gt^2[/tex]
[tex]-30 = 6t - \dfrac{1}{2}\times 9.8\times t^2[/tex]
4.9 t² - 6 t - 30 = 0
on solving the above equation
t = 3.16 s (neglecting the negative sign)
c) egg velocity just before it hit the ground
using equation of motion
v² = u² + 2 g h
v² = 0 + 2 x 9.8 x 31.84
v = √624.068
v = 24.98 m/s
d) The graphs are attached below.
In v-t graph velocity at the top most point is zero and after that it is negative
In a-t graph only acceleration due to gravity is acting in the negative direction.
The maximum height above the ground reached by the egg is 30 m.
The time taken for the released egg to hit the ground is 1.94 s.
The final velocity of the egg before it hits the ground is 25 m/s.
The given parameters:
- Speed of the dragon, v = 6 m/s
- Height of the dragon above the ground, h = 30 m
The maximum height above the ground reached by the egg is 30 m.
The time taken for the released egg to hit the ground is calculated as follows;
[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\ 30 = 6t + 4.9t^2\\\\ 4.9t^2 +6t - 30 = 0\\\\ t = 1.94 \ s[/tex]
The final velocity of the egg before it hits the ground is calculated as follows;
[tex]v_f = v_0 + gt\\\\ v_f = 6 + 9.8(1.94)\\\\ v_f = 25 \ m/s[/tex]
Learn more about vertical motion of projectiles here: https://brainly.com/question/11049671