Answer :
The coordinates of the vertices of quadrilateral ABCD are neither a parallelogram nor a trapezoid
The coordinates of the vertices of quadrilateral ABCD are:
A(0, −4)
B(−4, 3)
C(3, 4) , and
D(6, −1)
Slope of the line AB =[tex]\frac{3-(-4)}{-4-0} =-\frac{7}{4}[/tex]
Slope of the line BC =[tex]\frac{4-3}{3-(-4)} =\frac{1}{7}[/tex]
Slope of the line CD =[tex]\frac{-1-4}{6-3} =-\frac{5}{3}[/tex]
Slope of the line AD is
[tex]\frac{-1-(-4)}{6-0} =\frac{3}{6}\\=\frac{1}{2}[/tex]
Here we see that as the
Slope of the line AB ≠Slope of the line CD and
Slope of the line BC≠ Slope of the line AD
Therefore the coordinates of the vertices of quadrilateral ABCD are neither a parallelogram nor a trapezoid.
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