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A sinusoidal wave traveling on a string has a period of 0.20 s, a wavelength of 32 cm, and an amplitude of 3 cm. The speed of this wave is
A. 0.60 cm/s.
B. 6.4 cm/s.
C. 15 cm/s.
D. 160 cm/s.

Answer :

Answer:

[tex] v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}[/tex]

Explanation:

If we have a periodic wave we need to satisfy the following basic relationship:

[tex] v = \lambda f[/tex]

From the last formula we see that the velocity is proportional fo the frequency.

For this case we have the following info given by the problem:

[tex] T= 0.2 s, \lambda =32 cm* \frac{1m}{100cm} =0.32 m, A= 3cm*\frac{1m}{100 cm}=0.03 m[/tex]

We know that the frequency is the reciprocal of the period so we have this formula:

[tex] f = \frac{1}{T}[/tex]

And if we replace we got:

[tex] f =\frac{1}{0.2 s}= 5Hz[/tex]

Now since we have the value for the wavelength we can find the velocity like this:

[tex] v = 0.32 m * 5Hz = 1.6 \frac{m}{s}[/tex]

And if we convert this into cm/s we got:

[tex] v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}[/tex]

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