Answer :
Answer:
[tex] f_{blue}= \frac{3x10^8 m/s}{4x10^{-7} m}= 7.5 x10^{14} Hz[/tex]
So then our answer would be:
D. 7.50 × 10¹⁴Hz
Explanation:
For this case we know the frequency for the blue light, given by the problem:
[tex] \lambda_{blue}= 400 nm[/tex]
We can convert this into m like this:
[tex] \lambda_{blue}= 400 nm *\frac{10^{-9}m}{1nm}= 400x10^{-9}m = 4x10^{-7}m[/tex]
We know that the speed of light is a constant and is given by:
[tex] v_{light}= 3x10^{8} \frac{m}{s}[/tex]
And assuming that we have a fundamental wave, we need to satisfy the following basic relationship:
[tex] v = \lambda f[/tex]
And if we solve for the frequency from the last formula we got:
[tex] f = \frac{v}{\lambda}[/tex]
Now if we replace the values given we have:
[tex] f_{blue}= \frac{3x10^8 m/s}{4x10^{-7} m}= 7.5 x10^{14} Hz[/tex]
So then our answer would be:
D. 7.50 × 10¹⁴Hz