Answer :
Answer:
A sample of CH₂F₂ with a mass of 19 g contains 4.40ײ³ atoms of F
Explanation:
CH₂F₂ is called difluoromethane
Its molar mass is: 52 g/mol
1 mol of difluoromethane has 1 mol of Carbon, 2 moles of hydrogen and 2 moles of fluorine so we can begin from this relation:
52 g of difluoromethane have 2 moles of F
19 g of difluoromethane may have (19 .2 )/ 52 = 0.730 moles
Now we can determine the amount of atoms:
0.730 mol . 6.02x10²³ atoms / 1 mol = 4.40ײ³ atoms
The number of atoms of fluorine in 19 g of difluoromethane has been 4.399 [tex]\rm \bold{\times\;10^2^3}[/tex] atoms.
Difluormethane has been an organic gas consisting of 2 atoms of fluorine, and 1 atom of methane.
The difluoromethane has been consisted of the 2 atoms of fluorine in a molecule. The one mole of the compound has been equivalent to:
1 mole = molecular weight
Molecular weight of Difluoromethane = 52.023 g/mol.
1 mole difluoromethane has been consisted of 2 moles of fluorine.
52.023 g/mol Difluoromethane = 38 g/mol Fluorine
1 mol difluorethane = 2 moles fluorine
The moles of 19 g difluoromethane:
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of difluoromethane = [tex]\rm \dfrac{19}{52.023}[/tex]
Moles of difluoromethane = 0.365 mol.
The moles of fluorine in 0.365 mol Difluoromethane:
1 mole difluoromethane = 2 mole fluorine
0.365 mol Difluoromethane = 0.730 mol fluorine.
The number of atoms in a mole of elements has been equivalent to the Avogadro number.
1 mole = 6.023 [tex]\rm \times\;10^2^3[/tex] atoms
The number of fluorine atoms in 0.730 mol:
The number of F atoms = 0.730 × 6.023 [tex]\rm \times\;10^2^3[/tex] atoms
The number of F atoms = 4.399 [tex]\rm \times\;10^2^3[/tex] atoms
The number of atoms of fluorine in 19 g of difluoromethane has been 4.399 [tex]\rm \bold{\times\;10^2^3}[/tex] atoms.
For more information about the number of atoms, refer to the link:
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