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Which equation can be used to represent six added to twice the sum of a numbee and four is equal to one half of the difference of three and the number

Answer :

bayosanuade

Answer:  [tex]6 + 2 (x+4)[/tex] =   [tex]\frac{3}{2}[/tex][tex](3-x)[/tex]

Step-by-step explanation:

let the number be x , then :

six added to twice the sum of a number and four means :

[tex]6 + 2 (x+4)[/tex]

one half of the difference of three and the number means :

[tex]\frac{3}{2}[/tex][tex](3-x)[/tex]

combining the two , we have

[tex]6 + 2 (x+4)[/tex] = [tex]\frac{3}{2}[/tex][tex](3-x)[/tex]

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