[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2 \end{cases}\implies V=\cfrac{4\pi (2)^3}{3}\implies V=\cfrac{32\pi }{3} \\\\\\ V\approx 33.51032163829112\implies \stackrel{\textit{rounded up}}{V=34}[/tex]
The required volume of the sphere is 34 [tex]cm^{3}[/tex]
Let, r be the radius of a sphere.
Then the volume of the sphere = [tex]\frac{4}{3}\pi r^{3}[/tex] cubic unit
Radius of the given sphere = 2 cm
Taking, [tex]\pi =\frac{22}{7}[/tex]
∴ The volume of the sphere = [tex]\frac{4}{3}\pi r^{3}[/tex]
= [tex]\frac{4}{3}[/tex]×[tex]\frac{22}{7}[/tex]×[tex]2^{3}[/tex] [tex]cm^{3}[/tex]
= [tex]\frac{704}{21}[/tex] [tex]cm^{3}[/tex]
= 33.52 [tex]cm^{3}[/tex]
≈ 34 [tex]cm^{3}[/tex]
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