Answer :
You forgot to underline the element.
I can give you the oxidation number for the three elements
Li: +1 (this is the only oxidation number for this element)
O: -2 (this is the only oxidation number when it is not forming a peroxide)
Then: Oxidation number of Si is calculated from X +2(+1) + 3(-2) = 0
x +2 - 6 = 0
x = 6 - 2
x = 4
The oxidation number of Si is +4.
I can give you the oxidation number for the three elements
Li: +1 (this is the only oxidation number for this element)
O: -2 (this is the only oxidation number when it is not forming a peroxide)
Then: Oxidation number of Si is calculated from X +2(+1) + 3(-2) = 0
x +2 - 6 = 0
x = 6 - 2
x = 4
The oxidation number of Si is +4.
Determine the oxidation number of the element that is underlined within the compound.
Li2SiO3
Si= +4