Answer :
Answer:
Explanation:
Beat results due to difference in the frequency of tuning fork and sound produced by the flute at higher temperature.
frequency of tuning fork = 440 Hz
apparent frequency of flute at higher temperature = 440 x (343 / 340)
= 444 Hz (approx )
No of beats heard = 444 - 440 = 4 beats per second.
Answer:
we will get 440 beats per second
Explanation:
initial speed of sound in the flute, [tex]v_i=340\ m.s^{-1}[/tex]
frequency of the note played, [tex]f_i=440\ Hz[/tex]
speed of the sound after the air gets warmer, [tex]v_f=343\ m.s^{-1}[/tex]
Initial wavelength:
[tex]\lambda_i=\frac{v_i}{f_i}[/tex]
[tex]\lambda_i=\frac{340}{440}[/tex]
[tex]\lambda_i=0.773\ m[/tex]
We know that the wavelength of sound inside a tube with both the ends open is twice the length of the tube.
So,the length of the tube:
[tex]2L=\lambda_i[/tex]
[tex]2\times L=0.773[/tex]
[tex]L\approx0.3864\ m[/tex]
So the new frequency:
[tex]f_f=\frac{v_f}{\lambda_i}[/tex]
[tex]f_f=\frac{343}{0.773}[/tex]
[tex]f_f=443.88\ Hz[/tex]
we will get 440 beats per second