If a pilot pulls her 12.0 kg rollaboard suitcase along the ground with a force of 25. N for 10 M. The handle she pulls on makes an angle of 36.5 degrees with the horizontal. How much work does she do over the ten meter distance?

Answer :

Answer:

201 J

Explanation:

Work done by the pilot is defined by the equation

F d cos θ = 25 × 10 × cos 36.5 = 200.96 approx 201 J

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