Answer :
Answer:
[tex]a=2.275*10^{17}m/s^{2}[/tex]
Explanation:
The electron is negatively charged .The magnitude of force acting on on electron is
F=|e| E
Where E is electric field of long non conducting rod E=1/2πε₀r with linear charge density λ=6.7μC/m
From Newtons second laws
[tex]m_{e}a=|e|E\\[/tex]
the initial acceleration of electron is given by:
[tex]a=\frac{|e|E}{m_{e} }[/tex]
a=(|e|λ) /2πε₀rm= 2(|e|λ) / 4πε₀rm
Where 2 is multiplied on both numerator and denominator to simplify calculation
The electron is initially at distance r=9.3cm=0.093 m from rod
So
[tex]a=\frac{2*8.99*10^{9}*1.6*10^{-19}*6.7*10^{-6} }{0.093*9.109*10^{-31} }\\ a=2.275*10^{17}m/s^{2}[/tex]