A 32.82 gram sample of copper is heated in the presence of excess sulfur. A metal sulfide is formed with a mass of 41.10 g. Determine the empirical formula of the metal sulfide.

Answer :

Answer:

CU2S5

Explanation:

Step#1: Obtain the mass of each element present in the grams.

we have 32.8 g of copper and 41.10 g sulphur.

Step #2: Determine the number of moles of each type of atom present

⇒32.8g of copper * (1 mole copper/63.646)= 0.5164 mole copper atoms.

⇒ 41.08g of sulphur * (1mole suplhur/32.065)= 1.2811 mole suplhur atoms.

Step#3: Divide the number of moles of  each element by smallest number of moles.

⇒ 0.5164 mol Cu / 0.5164 = 1 mol Cu atoms.

⇒1.2811 mol S / 0.5164 = 2.480 mol S atoms

Step #5: Convert numbers to whole numbers.

⇒ 1 mol Cu atoms * 2 = 2 Cu atoms.

⇒ 2.480 S atoms * 2 = 5 S atoms

thus we have Cu2S5

Answer:

CuS.

Explanation:

Below is an attachment containing the solution.

Equation of the reaction:

2Cu(s) + S(g) --> Cu2S

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