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A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97. ??. Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to 6.0 mL. Calculate the new molarity of magnesium ion in the cell growth medium Be sure your answer has the correct number of significant digits. HM x 10

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okpalawalter8

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Answer:

 Answer: 760 uM

Explanation:

the addition of solvent to a solution in a such away that the volume of the solution increases and the concentration decreases is a process know as dilution

The concentration and the volume of the dilute and concentrated solution are given below as follows

     [tex]C_{1}V_{1}[/tex]                               [tex]= C_{f}V_{f}[/tex]

Concentrated solution          Dilute solution

Given that  M1 = 97.0uM

                  V1 = 47.0 mL

                 V2 = 6.0 mL

                 M2  = ?

Therefore M1V1   = M2V2

                M2      = M1V1/V2

                 M2 = (97*47)/6

               M2 = 760 uM

Answer: 760 uM

               

${teks-lihat-gambar} okpalawalter8

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