Answer :
Answer:
The mass of KF in the mixture is 1.067 grams
Explanation:
Step 1: Data given
Total weight of mixture (LiF+KF)= 5.93 grams
Mixture contains 3.94 grams of fluorine
Molar mass K = 39.10 g/mol
Molar mass F = 19.00 g/mol
Molar mass KF = 58.10 g/mol
Molar mass of lithium = 6.94 g/mol
Step 2: mass of KF and LiF
Mass KF = X grams
Mass LiF = 5.97 -X grams
Step 3: Calculate moles
Moles KF = x grams / 58.10 g/mol
Moles LiF = (5.97-X grams) / 25.94 g/mol
1 mol of KF contains 1 mol of F atoms.
1 mol of LiF contains 1 mol of F atoms.
moles of F in KF= moles of KF= x/58.10 g/mol
moles of F in LiF = moles of LiF= (5.97-x)/25.94g/mol
Total moles of Fluorine =(x/58.10)+((5.97-x)/25.94)
Step 4: Calculate mass
The total weight of Fluorine in sample
3.94 grams =((x/58.10)+((5.97-x)/25.94))*19g/mol
x = 1.067 grams
The mass of KF in the mixture is 1.067 grams