A 63 gram piece of magnesium absorbs 6689 joules of heat. The final temperature is 663 degrees Celsius. What was the initial temperature? ( the specific heat of magnesium is 1.023 j/g degrees Celsius)

Answer :

skyluke89

Answer:

[tex]559^{\circ}C[/tex]

Explanation:

When heat is supplied to a substance, the temperature of the substance increases according to:

[tex]Q=m C (T_f-T_i)[/tex]

where

Q is the amount of heat supplied

m is the mass of the substance

C is the specific heat capacity of the substance

[tex]T_i[/tex] is the initial temperature

[tex]T_f[/tex] is the final temperature

For the sample of magnesium in this problem, we have:

m = 63 g is the mass

Q = 6689 J is the hear supplied

C = 1.023 J/gC is the specific heat capacity

[tex]T_f=663^{\circ}C[/tex] is the final temperature

Solving the formula for [tex]T_i[/tex], we find the final temperature:

[tex]T_i = T_f-\frac{Q}{mC}=663-\frac{6689}{(63)(1.023)}=559^{\circ}C[/tex]

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