Answer :
Answer:
250 m
Explanation:
We expect the distance to be more because the sound level has decreased.
Sound level (in decibels) is related to distance by
[tex]r_2 = r_1 \times 10^{\frac{|L_1-L_2|}{20}}[/tex]
where [tex]L_1[/tex] is the sound level at a distance of [tex]r_1[/tex] and
[tex]L_2[/tex] is the sound level at a distance of [tex]r_2[/tex].
Using the values in the question,
[tex]r_{2} = 25\times10^{\frac{|75-55|}{20}} \text{ m}[/tex]
[tex]r_2 = 25\times10^1 \text{ m}= 250 \text{ m}[/tex]
As a note, when distance increases by 10, the sound level drops by 20 dB, which is what we have in the question.