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A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the other tower. He notes that it takes the wave 0.775 s to reach the opposite tower, 20.0 m away. If a 1 meter length of the rope has a mass of 0.300 kg, find the tension in the tightrope. N

Answer :

Explanation:

The given data is as follows.

      Distance (s) = 20 m

       time (t) = 0.775 s

Also, it is given that mass per 1 meter length (m) = 0.300 kg

Formula to calculate the velocity is as follows.

        Velocity (v) = [tex]\frac{s}{t}[/tex]

Putting the given values into the above formula as follows.

              v = [tex]\frac{s}{t}[/tex]

                 = [tex]\frac{20 m}{0.775 s}[/tex]

                 = 25.80 m/s

We know that,

              v = [tex]\sqrt{\frac{T}{m}}[/tex]

Taking square on both the sides, the formula will become as follows.

                      T = [tex]mv^{2}[/tex]

                         = [tex]0.3 kg \times 25.80[/tex]          

                         = 199.692 N

Therefore, we can conclude that tension in the given tightrope is equal to 199.692 N .