Answer :
Answer:
- 315 kg
Explanation:
1. Word reaction:
- Aluminum trioxide + hydrogen → aluminium metal + water
2. Chemical equation:
This is the unbalanced equation that represents chemical reaction:
[tex]Al_2O_3+H_2\rightarrow Al+H_2O[/tex]
3. Balanced equation
This is the balanced chemical equation that represents the reaction:
[tex]Al_2O_3+3H_2\rightarrow 2Al+3H_2O[/tex]
4. Calculate the number of moles of aluminium oxyde available:
- Molar mass = 101.960 g/mol
- Mass = 700.0 kg
Formula:
- Number of moles = mass in grams / molar mass
Substitute:
- Number of moles = 700.0 kg × 1,000 g/ kg / 101.960 g/mol = 6,865.4mol
5. Mole ratio:
From the balanced chemical equation:
[tex]\dfrac{2molAl}{1molAl_2O_3}[/tex]
6. Number of moles of aluminium
[tex]6,865.4molAl_2O_2\times \dfrac{2molAl}{1molAl_2O_3}=13,730.8molAl[/tex]
7. Convert to mass
- Atomic mass of aluminium: 26.981g/mol
- Mass = atomic mass × number of moles
- Mass = 26.981g/mol × 13,730.8mol = 370,470.7g
This is a theoretical yield.
8. Actual yield
Use the formula of percent yield.
- Percent yield = (actual yield) / (theoretical yield) × 100
- Actual yield = theoretical yield × percent yield / 100
- Actual yield = 370,470.7 g × 85/100 = 314,900.1 g
- 314,900.1 g × 1kg/1,000g = 314.9kg = 315kg ← answer