The electric field just above the surface of the charged drum of a photocopying machine has a magnitude E of 2.3 ✕ 105 N/C. The drum has a length of 55 cm and a diameter of 11 cm. What is the total charge on the drum?

Answer :

lublana

Answer:

[tex]1.68\times 10^{-7} C[/tex]

Explanation:

Electric field=[tex]E=2.3\times 1065 N/C[/tex]

Length of drum=l=55 cm=[tex]\frac{55}{100}=0.55 m[/tex]

Using 1 m=100 cm

Diameter ,d=11 cm=[tex]\frac{11}{100}=0.11 m[/tex]

We have to find the total charge on the drum.

We know that

[tex]q=\sigma A=\pi\epsilon_0Edl[/tex]

[tex]\epsilon_0=8.85\times 10^{-12} C^2/Nm^2[/tex]

[tex]\pi=3.14[/tex]

Substitute the values

[tex]q=3.14\times 8.85\times 10^{-12}\times 2.3\times 10^5\times 0.55\times 0.11}[/tex]

[tex]q=1.68\times 10^{-7} C[/tex]

Other Questions