Answer :
Answer:
The cannonball will be spend 4.04 seconds before striking the ground.
Explanation:
Given:
vertical height = 80 m
horizontal velocity = 25m/s
Initial vertical velocity, Vy= 0
Applying equations of motion;
s = Vy*t + ¹/₂gt²
80 = ¹/₂*9.8t²
4.9t² = 80
t² = 80/4.9
t² = 16.327
[tex]t = \sqrt{16.327} =4.04 s[/tex]
Therefore, the cannonball will be spend 4.04 seconds before striking the ground.
Answer:
2.23 s.
Explanation:
Given:
S = 80 m
voy = 0 m/s
vox = 25 m/s
g = 9.81 m/s^2
Using equation of motion,
S = vo*t + 1/2 * g * t^2
80 = 0 + 4.905t^2
Solving this equation, we have:
t = sqrt(16.31)
= 4.039 s
Therefore, t = 4.04 s.