Answer :
Answer: It will take 0.50 minutes for it to decompose to 28.2% of its initial value
Explanation:
Integrated rate law for second order kinetics is given by:
[tex]\frac{1}{a}=kt+\frac{1}{a_0}[/tex]
a= concentration left after time t = [tex]\frac{28.2}{100}\times 1.77=0.50M[/tex]
k = rate constant =[tex]2.85M^{-1}min^{-1}[/tex]
[tex]{a_0}[/tex] = initial concentration = 1.77
t= time taken for decomposition
[tex]\frac{1}{0.50}=2.85\times t+\frac{1}{1.77}[/tex]
[tex]t=0.50min[/tex]
Thus it will take 0.50 minutes for it to decompose to 28.2% of its initial value