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During a chemical​ reaction, the temperature in a beaker decreased every minute by the same number of degrees. The temperature was 63degreesF at 11​:30 a.m. By 11​:54 ​a.m., the temperature had dropped to minus12degreesF. By how many degrees did it change each​ minute?

Answer :

joseaaronlara

Answer:

The answer to your question is "The temperature drops 3.125°F each minute".

Explanation:

Data

Initial temperature = 63°F          Initial time = 11:30 am

Final temperature = -12°F           Final time = 11:54 am

Process

1.- Calculate the difference of minutes

    11:54 - 11:30 = 24 min

2.- Calculate the difference of temperature

    63°F - (-12°F) = 63°F + 12°F = 75°F

3.- Divide the difference of temperature by the difference of time

                75/24 = 3.125

4.- Conclusion

   The temperature drops 3.125°F each minute.

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