Answer :
Kinetic energy of the ball at the highest point of its motion is 176.42 J
Explanation:
Kinetic energy = 0.5 x Mass x Velocity²
Mass, m = 0.150 kg
At highest point the baseball is only having horizontal velocity.
Horizontal velocity, v = 56 cos 30 = 48.50 m/s
Substituting
Kinetic energy = 0.5 x Mass x Velocity²
Kinetic energy = 0.5 x 0.15 x 48.50²
Kinetic energy = 176.42 J
Kinetic energy of the ball at the highest point of its motion is 176.42 J
The kinetic energy of the ball at the highest point of its motion is equal to 176.42 Joules.
Given the following data:
- Mass of baseball = 0.150 kg
- Speed of baseball = 56.0 m/s
To calculate the kinetic energy of the ball at the highest point of its motion:
The horizontal velocity of an object.
The baseball has a horizontal velocity at the highest point of its motion, which is given by this:
[tex]V_y=Vcos\theta\\\\V_y=56.0 \times cos30\\\\V_y=56.0 \times 0.8660\\\\V_y=48.50\;m/s[/tex]
The formula for kinetic energy.
Mathematically, kinetic energy (K.E) is given by this formula;
[tex]K.E = \frac{1}{2} MV^2[/tex]
Where:
- K.E is the kinetic energy.
- M is the mass of an object.
- V is the velocity of an object.
Substituting the given parameters into the formula, we have;
[tex]K.E = \frac{1}{2} \times 0.150 \times 48.50^2\\\\K.E =0.075 \times 2352.25[/tex]
K.E = 176.42 Joules.
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