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Write the slope-intercept form (y=mx+b) of the equation of the line through the given points.​

Write the slope-intercept form (y=mx+b) of the equation of the line through the given points.​ class=

Answer :

Answer:   [tex]y = \frac{4}{5}x-\frac{3}{5}[/tex]

m = 4/5 is the slope

b = -3/5 is the y intercept

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First find the slope

m = (y2 - y1)/(x2 - x1)

m = (-3 - 1)/(-3 - 2)

m = -4/(-5)

m = 4/5

Then use point-slope form

[tex]y - y_1 = m(x - x_1)\\\\y - 1 = \frac{4}{5}(x - 2)\\\\y - 1 = \frac{4}{5}x + \frac{4}{5}(-2)\\\\y - 1 = \frac{4}{5}x - \frac{8}{5}\\\\y = \frac{4}{5}x - \frac{8}{5} + 1\\\\y = \frac{4}{5}x - \frac{8}{5} + \frac{5}{5}\\\\y = \frac{4}{5}x + \frac{-8+5}{5}\\\\y = \frac{4}{5}x - \frac{3}{5}\\\\[/tex]

The equation is in the form y = mx+b with m = 4/5 as the slope and b = -3/5 as the y intercept.

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