Answer :
Explanation:
It is known that wave intensity is the power to area ratio.
Mathematically, I = [tex]\frac{P}{A}[/tex]
As it is given that power is 28.0 W and area is [tex]7 \times 10^{-5} m^{2}[/tex].
Therefore, sound intensity will be calculated as follows.
I = [tex]\frac{P}{A}[/tex]
= [tex]\frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}[/tex]
= [tex]0.318 \times 10^{5} W/m^{2}[/tex]
or, = [tex]3.18 \times 10^{4} W/m^{2}[/tex]
Thus, we can conclude that sound intensity at the position of the microphone is [tex]3.18 \times 10^{4} W/m^{2}[/tex].