Answer :
Answer:
[tex]I_{avg}=0.3135A[/tex]
Explanation:
Given data
Voltage V=3.70V
time t=7.20h=25920s
Energy E=3.00×10⁴J
To find
Average current I
Solution
As we know that power is:
[tex]Power=\frac{Energy}{y\time} \\Power=\frac{3.00*10^{4}J }{25920s}\\ Power=1.16W\\Also\\Power=V_{voltage}*I_{avg}\\ 1.16W=3.70V*I_{avg}\\I_{avg}=1.16/3.70\\I_{avg}=0.3135A[/tex]