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Toretto and O’Conner graphed two different quadratic functions in vertex form. Toretto graphed f(x)=(x+3)^2+1 and O’Conner graphed g(x) =-(x-3)^2+1 . Both of them drew the same graph.

Toretto and O’Conner graphed two different quadratic functions in vertex form. Toretto graphed f(x)=(x+3)^2+1 and O’Conner graphed g(x) =-(x-3)^2+1 . Both of th class=

Answer :

PSN03

Yo sup??

By observing the graph we can say that minimum value of Toretto graph occurs at x=-3

whereas the minimum value of OConner graph occurs at x=3 .

In the given figure the minimum value is at x=3

therefore OConner is correct because the vertex is (3,1)

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is this c or d??

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