If a ball is thrown directly up at 30 meters per second, its height (in meters) after t seconds is given by h(t) = 30t - 5t^2. What is the maximum height (in meters) attained by the ball?

Answer :

amna04352

Answer:

45m

Step-by-step explanation:

t = -30/(-2×5) = 3

Max height at t = 3

30(3) - 5(3)² = 45m

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