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Water enters the pump of a steam power plant as saturated liquid at 20 kPa at a rate of 45 kg/s and exits at MPa. Neglecting the changes in kinetic and potential energies and assuming the process to be reversible, determine the power input to the pump.

Answer :

Answer:power input =44.85kw

Explanation:

V=0.001017m³/kg

The power input of the pump

W=mv(p2-p1)

=45*0.001017*(1000-20)

45*0.001017*980

44.85kw

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