Answer :
The question is incomplete, complete question is :
Calculate the change in enthalpy associated with the combustion of 492.2 g of sulfur. Report your answer with four significant figures. Do not include a comma in your answer.
[tex]S(s)+O_2(g)\rightarrow SO_2(g) ,\Delta H_C=-296.8 kJ/mol[/tex]
Answer:
-4,565 kJ the change in enthalpy associated with the combustion of 492.2 grams of sulfur.
Explanation:
Enthalpy change when 1 mole of sulfur is combusted = -296.8 kJ
Mass of sulfur = 492.2 g
Moles of sulfur = [tex]\frac{492.2 g}{32 g/mol}=15.38 mol[/tex]
Enthalpy change when 15.38 moles of sulfur:
[tex]-296.8 kJ\times 15.38=-4,565.155 kJ\approx -4,565 kJ[/tex]
-4,565 kJ the change in enthalpy associated with the combustion of 492.2 grams of sulfur.