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The population of a town increased by 16 2 3 % in 1990 and 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?

Answer :

sqdancefan

Answer:

 38,500

Step-by-step explanation:

162/3% = (16 2/3)/100 = (50/3)/100 = 50/300 = 1/6

1/6 of the original population was ...

  1/6 × 30,000 = 5,000

So the population at the end of 1990 was

  30,000 +5,000 = 35,000.

In 1991, 10% of that number was added, so the population at the end of 1991 was ...

  35,000 + 0.10×35,000 = 38,500

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