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Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequency of 8.88×1014 Hz . What is the change in energy, ΔE, that the electron undergoes to decay to its ground state?

Answer :

Answer: 5.884×10^-19 J

Explanation:

The change in energy will be the product of the planck constant and the frequency of radiation.

ΔE = hf

Where h = planck constant = 6.626×10^-34 m²kg/s

f = 8.88×10^14 Hz

ΔE = 6.626×10^-34 × 8.88×10^14 = 58.84×10^-20 = 5.884×10^-19 J

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