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Can someone help with this assignment for C++? We were just introduced to loops, specifically while loop, do-while loop, for loop, and nested loops.
Write a program that reads a sequence of integers and prints the following:
The number of odd and even numbers of inputs
Use a sentinel value to signal the end of inputs. If the sentinel value is the first you enter, give a message "NO input is entered!".
Input Validation: Do not accept a negative number.

Answer :

teobguan2019

Answer:

  1. #include <iostream>
  3. using namespace std;
  5. int main()
  6. {
  7.    int value;
  8.    int oddCount = 0;
  9.    int evenCount = 0;
  10.    
  11.    cout<<"Input a positive number: ";
  12.    cin>> value;
  13.    
  14.    if(value == -1){
  15.        cout<<"NO input is entered!";
  16.        return 0;
  17.    }
  18.    
  19.    if(value < -1) {
  20.          cout<<"The input number must be positive";
  21.          return 0;
  22.    }
  23.    
  24.    while(value != -1){
  25.        
  26.        if(value % 2 == 0){
  27.            evenCount++;
  28.        }else{
  29.            oddCount++;
  30.        }
  31.        cout<<"Input a positive number: ";
  32.        cin>>value;
  33.        if(value < -1){
  34.              cout<<"Wrong input number\n";
  35.              return 0;
  36.        }
  38.    }
  39.    
  40.    cout<<"Number of odd number: "<< oddCount<<"\n";
  41.    cout<<"Number of even number: "<< evenCount;
  42.  
  43.    return 0;
  44. }

Explanation:

Firstly, create three variables, value, oddCount and evenCount (Line 7-9). The value variable is to hold the input number from user (Line 11 -12). oddCount and evenCount are to track the number of occurrence of even and odd number of the user input (Line 21-25).

The sentinel value here is -1 and therefore if user enter -1 as first input, the message "NO input is entered!" will be displayed. (Line 14).

If user input a negative value other than -1 , display the alert message to user and terminate the program (Line 19-22).

We check if the value modulus by two is zero, this means it is an even number and then increment evenCount by one (Line 26-27). Otherwise increment oddCount by one (Line 28-29).  

After that prompt the user to input another number again and repeat the loop (Line 31-36). So long as the user don't enter -1, the while loop will just keep running.

At last, print the number of odd and even number (Line 40-41).

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