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I NEED HELP ASAP MISSING ASSIGNMENTS HAVE TO BE TURNED IN TOMORROW \
i will mark you as brainlyest

I NEED HELP ASAP MISSING ASSIGNMENTS HAVE TO BE TURNED IN TOMORROW \ i will mark you as brainlyest class=

Answer :

Part 1:  Circumference of circle  = [tex]105.20[/tex] inches & Area of circle = [tex]880.97 inches^{2}[/tex]

Part 2: Area of circle = [tex]3.14 ft^{2}[/tex]

Part 3: Area of square not covered by  circle = [tex]29.69inches^{2}[/tex].

Step-by-step explanation:

Part 1:

We have radius of circle as [tex]16\frac{3}{4} = 16.75 inches[/tex] . Let's find area & circumference of circle:

Circumference of circle = [tex]2\pi r[/tex]

⇒ Circumference of circle = [tex]2\pi r[/tex]

⇒ Circumference of circle = [tex]2\pi r[/tex] = [tex]2(3.14)(16.75)[/tex]

⇒ Circumference of circle  = [tex]105.20[/tex] inches

Area of circle = [tex]\pi r^{2}[/tex]

⇒ Area of circle=  [tex]\pi r^{2}[/tex]

⇒Area of circle = [tex]\pi r^{2}[/tex] = [tex](3.14)(16.75)^{2}[/tex]

⇒ Area of circle = [tex]880.97 inches^{2}[/tex]

Part 2:

Circumference of circle = [tex]2\pi r[/tex] = [tex]6.28ft[/tex]

[tex]2\pi r = 6.28[/tex]

[tex]r = \frac{6.28}{2\pi } = \frac{6.28}{2(3.14)} = 1 ft[/tex]

Area of circle = [tex]\pi r^{2}[/tex]

⇒Area of circle = [tex]\pi r^{2}[/tex] = [tex](3.14)(1)^{2}[/tex]

⇒ Area of circle = [tex]3.14 ft^{2}[/tex]

Part 3:

Perimeter of square = [tex]4a[/tex] , a is side of square.

⇒ [tex]4a = 47[/tex]

⇒ [tex]a = \frac{47}{4}[/tex]

⇒ a = [tex]11.75 inch[/tex]

Since radius of circle inscribed in square is half of side of square i.e.

[tex]radius = \frac{a}{2}\\ radius = r = \frac{11.75}{2}[/tex]

[tex]r = 5.875inch[/tex]

Now, Area of square not covered by  circle = Area of square - area of circle

⇒ [tex]a^{2} - \pi r^{2}[/tex]

⇒ [tex]11.75^{2} - 3.14(5.875)^{2}[/tex]

⇒ [tex]29.69inches^{2}[/tex]

Area of square not covered by  circle = [tex]29.69inches^{2}[/tex].

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