Answer:
[tex]\large \boxed{y = (x - 5)^{2} + 2 }[/tex]
Step-by-step explanation:
y = x² - 10x + 27
y = ax² + bx + c
This is the general form of the equation for a parabola.
We must convert it to the vertex form
y = (x - h)² + k, where (h,k) are the coordinates of the vertex.
We can do this by completing the square.
[tex]\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}[/tex]The figure below shows that your parabola has its vertex at (5,2).
