Answer :
Answer:
Therefore,
1. The value of Discriminant of f(x) is
[tex]Discriminant =\sqrt{124}[/tex]
2. f(x) has Two Distinct Real number zeros.
Step-by-step explanation:
Given:
[tex]f(x)=6x^{2}+10x-1[/tex]
To Find:
1 . What is the value of the discriminant of f(x) = ?
2. How many distinct real number zeros does f(x) have = ?
Solution:
For a Quadratic Equation
[tex]ax^{2}+bx+c=0[/tex]
The Discriminant is given as
[tex]Discriminant = \sqrt{b^{2}-4ac}[/tex]
So on Comparing and substituting we get
a = 6 ; b = 10 ; c = -1
Therefore,
[tex]Discriminant = \sqrt{10^{2}-4\times 6\times -1}=\sqrt{124}[/tex]
Now if,
[tex]Discriminant > 0[/tex] .....f(x) has Two Distinct Real number zeros
here,
[tex]Discriminant =\sqrt{124}[/tex] Which is greater than zero
Hence f(x) has Two Distinct Real number zeros
Therefore,
1. The value of Discriminant of f(x) is
[tex]Discriminant =\sqrt{124}[/tex]
2. f(x) has Two Distinct Real number zeros.