A rectangle has a height of 444 and a width of x^2+3x+2x 2 +3x+2x, squared, plus, 3, x, plus, 2. Express the area of the entire rectangle. Expression should be expanded. A rectangle has a height of 4 and a width of x squared + 3x + 2.

Answer :

The area of the rectangle is [tex]4x^2+12x+8[/tex]

Explanation:

Given that the height of the rectangle is 4.

The width of the rectangle is [tex]x^2+3x+2[/tex]

Area of the rectangle:

The area of the rectangle can be determined using the formula,

[tex]Area=height\times width[/tex]

where height = 4 and width = [tex]x^2+3x+2[/tex]

Substituting the values in the above formula, we have,

[tex]Area=4(x^2+3x+8)[/tex]

Let us expand the expression by multiplying the terms within the bracket, we get,

[tex]Area=4x^2+12x+8[/tex]

Thus, the area of the entire rectangle is [tex]4x^2+12x+8[/tex]

Answer:

x^3+7x^2+14x+8

Step-by-step explanation:

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