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There is a bag with only milk and dark chocolates.
The probability of randomly choosing a dark chocolate is
7
9
.
There are 42 dark chocolates in the bag and each is equally likely to be chosen.
Work out how many milk chocolates there must be.

Answer :

opudodennis

Answer:

12 milk chocolates.

Step-by-step explanation:

-We know that probabilities add upto 1:

[tex]P(milk)+P(dark)=1\\\\P(milk)+\frac{7}{9}=1\\\\P(milk)=\frac{2}{9}[/tex]

Let X be the total number of chocolates. We know that probability is the successful events divided by the total number of events:

[tex]P(dark)=\frac{dark \ events}{total \ events}\\\\\\\frac{7}{9}=\frac{42}{X}\\\\X=54[/tex]

#We subtract the number of dark chocolates from X to get the number of milk chocolates:

[tex]N_m=X-N_d\\\\=54-42\\\\=12[/tex]

Hence, there must be 12 milk chocolates.

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