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In acid dilution problem, describe how you created 500 ml of a 5.5 M HCl solution from the 11.6 M stock solution. Show your calculations and give details about the equipment used, which solutions you mixed together, and amounts of each.

Answer :

Answer: 237 ml of stock solution is taken in a 500 ml volumetric flask and diluted with water until the 500 ml mark to obtain 5.5 M diluted solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock [tex]HCl[/tex] solution = 11.6 M

[tex]V_1[/tex] = volume of stock [tex]HCl[/tex] solution = ?

[tex]M_2[/tex] = molarity of dilute [tex]HCl[/tex] solution = 5.5 M

[tex]V_2[/tex] = volume of dilute [tex]HCl[/tex] solution = 500 ml

[tex]11.6\times V_1=5.5\times 500[/tex]

[tex]V_1=237ml[/tex]

Thus 237 ml of stock solution is taken in a 500 ml volumetric flask and diluted with water until the 500 ml mark to obtain 5.5 M diluted solution

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