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Examine the following set of ionization energy values for a certain element. How many valence electrons does an atom of the neutral element possess? Ionization step - Ionization energy (kJ/mol) IE1 - 1012 IE2 - 1903 IE3 - 2912 IE4 - 4956 IE5 - 6273 IE6 - 22233 IE7 - 25997 IE8 - 27575 Express your answer numerically as an integer.

Answer :

Answer:

5

Explanation:

For knowing the number of valence electrons in the neutral element, we first need to see the change in ionization energy between every step.

[tex]IE_2-IE_1= 1903-1012= 891 kJ/mol[/tex]

[tex]IE_3-IE_2= 2912-1903=1009kJ/mol[/tex]

[tex]IE_4-IE_3=4956-2912=2044kJ/mol[/tex]

[tex]IE_5-IE_4= 6273-4956=1317kJ/mol[/tex]

[tex]IE_6-IE_5= 22233-6273= 15960kJ/mol[/tex]

Looking at the values above, we find that there is huge change at step 6, that means large amount of energy was required at step 6 which indicates that at this step the kernel electron was taken out.

Thus the element in the question has 5 electrons in it's valence shell as the 6th electron was kernel electron.

Answer:

The number of valence electrons in the given neutral element is 5 in number.

Explanation:

Ionization energy can be defined as the energy required to remove an electron from the gaseous state.

The energy required to remove the valence electron from the neutral state is higher as compared to bonds electrons.

To identify the number of valence electron in an element neutral state, the change in the ionization energy on removal of electrons is considered.

The change in ionization energy for removal of electrons can calculated by:

                     Change in ionization energy [tex]\left ( \RM \Delta IE \right )[/tex]  = [tex]\rm IE_2\; - IE_1[/tex]

For 1st electron the [tex]\RM \Delta IE_1[/tex] = 891 kJ/mole

For 2nd electron the [tex]\RM \Delta IE_2[/tex] = 1009 kJ/mole

For 3rd electron the [tex]\RM \Delta IE_3[/tex] = 2044 kJ/mole

For 4th electron the [tex]\RM \Delta IE_4[/tex] = 1317 kJ/mole

For 5th electron the [tex]\RM \Delta IE_5[/tex] = 15960 kJ/mole

For 6th electron the [tex]\RM \Delta IE_6[/tex] = 3764 kJ/mole

For 7th electron the [tex]\RM \Delta IE_7[/tex] = 1578 kJ/mole

It is evident that the highest energy is required for the removal of 5th electron from the neutral element. Therefore, the number of valence electrons possessed by the given neutral element is 5.

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