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A mass m0 is attached to a spring and hung vertically. The mass is raised a short distance in the vertical direction and released. The mass oscillates with a frequency f0 . If the mass is replaced with a mass nine times as large, and the experiment was repeated, what would be the frequency of the oscillations in terms of f0

Answer :

Answer:

The frequency of the oscillations in terms of fo will be f2=fo/3

E xplanation:

T= [tex] 2pie\frac sqrt {m}{k}[/tex]

 [tex]\frac {{f2}/times {fo}} [/tex]=1:3

⇒f2=fo\3

Here frequency f is inversely poportional to square root of mass m.

so the value of remainder of frequency f2 and fo is equal to 1:3.

⇒[tex]\frac{f2} {f1}[/tex] = [tex] \frac sqrt{m1}[m2}[/tex]

⇒[tex]\frac{f2}{fo}[/tex] = 1:3

⇒f2=[tex]\frac{fo} {3}[/tex]

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