A fruit company delivers in 2 types of boxes: Large and small . A delivery of 3 large boxes and 3 small boxes has a total weight of 131 kilograms. How much does each box weigh?

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms. A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms. How much does each type of box weigh?

My answer:

Let:

x is the weight of a large box

y is the weight of a small box

Given that:

A delivery of 5 large boxes and 3 small boxes has a total weight of 131

<=> 5x + 3y = 131 (1)

A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms

<=> 2x + 6y = 116 <=> x= 58 - 3y (2)

Substitute (2) into (1), we have:

5x + 3y = 131 (1)

<=> 5(58 - 3y ) + 3y = 113

<=> y = 13.25

Solving this problem, we get the solution is:

y = 13.25 and x =18.25

So the weigh of the small box is 13.25 kg and the weigh of the large box is 18.25 kg

Hope it will find you well.

ifesynwajesuschrist ifesynwajesuschrist · Answer 2 · 2025-03-27T15:59:40-04:00

Completion of question

A fruit company delivers in 2 types of boxes: Large and small . A delivery of 3 large boxes and 3 small boxes has a total weight of 131 kilograms and 5 small boxes and 7 large boxes weigh 240 kilograms. How much does each box weigh?

Answer:

Small box weighs 10.83

Big box weighs 32.83

Step-by-step explanation:

According to the question,2 different boxes are been delivered by a fruit company(The large box and the small box)

And this question also says that these 3 small boxes and another 3 larger boxes weigh 131 kilograms and another set of boxes were delivered(5 larger boxes and 7 smaller boxes) which weighed 240 kilograms.

Now we were asked to find the weight of this 2 kind of boxes(the larger ones and the smaller ones)

Let the weight of the smaller box be Y

Let the weight of the bigger box be X

3X+3Y= 131_______ equation 1

5X+7Y= 240_______ equation 2

Using substitution method,solve for X

In equation 1: X=(131-3Y)/3

apply the above in equation 2 and we have

5×[(131-3Y)/3] + 7Y= 240

(655-15Y)/3 + 7Y= 240

655-15Y+21Y= 720

6Y= 65

Y=10.83

Now substitute Y= 10.83 in equation 1

3X + 3(10.83) = 131

X= (131-32.5)/3

X=32.83

Therefore, the weight of the smaller and bigger boxes are 10.83 and 32.83 respectively.