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A 110-kg football player running at 8.00 m/s catches a 0.410-kg football that is traveling at 25.0 m/s. Assuming the football player catches the ball with his feet off the ground with both of them moving horizontally, calculate:

the final velocity if the ball and player are going in the same direction

a
7.88 m/s

b
8.06 m/s

c
8.00 m/s

d
890 m/s

Answer :

Final Velocity = 8.06 m/s

Option : B

Explanation:

Let [tex]m_1[/tex]be the mass of player,

     [tex]m_2[/tex] be the mass of the ball,

     [tex]u_1[/tex] be the initial speed of the player,

     [tex]u_2[/tex] be the initial speed of the ball and

     v be the final speed of the player after the catching the ball.

Applying conservation of momentum, we can solve for the final speed of the player after the catching the ball when the ball and player move in the same direction.

Here:

[tex]m_1[/tex] = 110 Kg

[tex]m_2[/tex] = 0.410 Kg

[tex]u_1[/tex]  = 8.0 m/s

[tex]u_2[/tex] = 25.0 m/s

[tex]\mathrm{m}_{1} \mathrm{u}_{1}+\mathrm{m}_{2} \mathrm{u}_{2}=\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right) \mathrm{v}[/tex]

[tex]\mathrm{V}=\frac{\mathrm{m}_{1} \mathrm{u}_{1}+\mathrm{m}_{2} \mathrm{u}_{2}}{\mathrm{m}_{1}+\mathrm{m}_{2}}[/tex]

   = [tex]\frac {{{110\ Kg} \times {8.0\ m/s}}\ +\ {{0.410\ Kg} \times {25.0\ m/s}}} {110 + 0.410}[/tex]

  = [tex]\frac {880 + 10.25} {110.41}[/tex]

V = 8.06 m/s

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