Answer:
Explanation:
(a) The applied force has two components Fx and Fy. The Fx component is the only one that does work
[tex]W_{x}=F_{x}x=(16N)cos(25)(2.2m)=31.9J[/tex]
(b) There in no net force in the vertical component
[tex]F_{N}-F_{y}-F_{g}=0\\F_{N}=F_{y}+F_{g}=(16N)sin(25)+(2.5kg)(9.8\frac{m}{s^{2}})=31.26N[/tex]
(c)
[tex]F_{g}=Mg=(2.5kg)(9.8\frac{m}{s^{2}})=24.5N[/tex]
(d)
[tex]F_{T}=F_{x}=(16N)cos(25)=14.5N[/tex]
I attached an scheme of the force diagram
