Answer :
Answer: F=0.075N
Explanation:
T*cos(θ) = mg=0.005X9.8
T*cos(θ)=0.049N
T = 0.049/cosθ
F = k*q1*q2 / r2
F = 8.9875 * 10^9 * q1*q2 / r^2 q1
F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2
F=0.2246875/r^2
r= 2Lsinθ = 2 x 1 x sinθ =2sinθ
Kindly check the attached for further solution
The magnitude of the force exerted by one ball on the other is [tex]0.05625/sin^{2} \theta[/tex] .
Electrostatic Force:
When two or more charged particles are held at some distance, then the force exerted by one charged particle on the other is known as electrostatic force.
Given data:
The mass of aluminum foil is, m = 5.0 g = 0.005 kg.
The length of the thread is, L = 1.0 m.
The magnitude of the charge on each ball is, [tex]q =5.0 \times 10^{-6} \;\rm C[/tex].
The expression for the force exerted by one ball to the other is given as,
[tex]F = \dfrac{k \times q^{2}}{d^{2}}[/tex]
here,
k is Coulomb's constant and d is the horizontal component of the length of thread and its value is,
[tex]d = 2L sin\theta[/tex]
[tex]\theta [/tex] is the angle made by the thread with the vertical.
Solving as,
[tex]F = \dfrac{9 \times 10^{9} \times (5.0 \times 10^{-6})^{2}}{(2L sin \theta)^{2}}\\\\\\ F = \dfrac{9 \times 10^{9} \times (5.0 \times 10^{-6})^{2}}{(2 \times 1.0 \times sin \theta)^{2}}\\\\\\ F = \dfrac{0.05625}{sin^{2} \theta}[/tex]
Thus, we can conclude that the magnitude of force exerted by one ball on the other is [tex]0.05625/sin^{2} \theta[/tex] .
Learn more about the electrostatic force here:
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