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Permanganate ion reacts in basic solution with oxalate ion to form carbonate ion and solid manganese dioxide. Balance the skeleton ionic equation for the reaction between NaMnO4 and Na2C2O4 in basic solution: Fill in all blanks with numbers so if the term is not in the equation make it 0.

a. ________MnO4- (aq) + _______C2O42- (aq)+
b. ______H+(aq) + _____OH-(aq) +
c. ______H2O(l) ⟶_______ MnO2(s) +
d. _______CO32- (aq) +_______ H+(aq) +
e. ______ OH-(aq) + _______H2O(l)

Answer :

Answer:

a. 2 MnO₄⁻ (aq) +3 C₂O₄²⁻(aq) +

b. 0 H⁺(aq) +  4OH⁻ (aq) +

c. 0 H₂O(l) → 2 MnO₂(s) +

d. 6CO₃²⁻(aq) + 0 H⁺(aq) +

e.  0 OH⁻(aq) + 2H₂O(l)

Explanation:

At first you write skeleton chemical equation and then balanced by using ion electron method

Permanagante ion reacts in basic medium by the following

                             MnO₄⁻ + 2H₂O +3e⁻ → MnO₂ + 4 OH⁻ ......................(i)

MnO₄⁻ acts as a oxidising agent which oxidised oxalate ion into carbonate ion and reduced itself into solid MnO₂.

                       C₂O₄²⁻ + 4 OH⁻ → 2 CO₃²⁻ + 2e⁻ + 2H₂O .....................(ii)

Multiplying equation (i) by factor 2 and equation (ii) by factor 3

                    rewrite the equation

           2 MnO₄⁻ + 4 H₂O +6 e⁻ → 2 MnO₂ + 8 OH⁻---------------------------(iii)

           3 C₂O₄²⁻ + 12 OH⁻ → 6 CO₃²⁻ + 6 e⁻ + 6 H₂O-----------------------(iv)

Noe add the equation (iii) + (iv)

we get  2 MnO₄⁻ + 3 C₂O₄²⁻ + 4 OH⁻ →  6 CO₃²⁻ + 2 MnO₂ + 2 H₂O

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