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Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm .Part AAt a distance from the slits which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 25.0 ∘ from the centerline?

Answer :

Answer:

The phase difference between waves 31.7 rad

Explanation:

Given :

Wavelength [tex]\lambda = 540 \times 10^{-9}[/tex] m

Separation between two slit [tex]d = 0.370 \times 10^{-3}[/tex] m

Angle [tex]\theta =[/tex] 25°

From the formula of phase difference,

  [tex]\delta = \frac{2\pi d }{\lambda} \sin \theta[/tex]

Where [tex]\delta =[/tex] phase difference

[tex]\delta = \frac{2 \times \pi \times 0.370 \times 10^{-3} }{540 \times 10^{-9} } \sin 25[/tex]

[tex]\delta = 31.7[/tex] rad

Therefore, the phase difference between waves 31.7 rad

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