Answer:
[tex]SinQ=\frac{15}{17}[/tex]
Step-by-step explanation:
We draw the right triangle as shown in the image attached.
Δ QRS
Where R is the right angle
Given
QR = 8
QS = 17
Now, using Pythagorean Theorem, we can find RS:
[tex]QR^2+RS^2=QS^2\\8^2+RS^2=17^2\\RS^2=17^2-8^2\\RS^2=225\\RS=\sqrt{225}\\RS=15[/tex]
Now, we know the ratio Sine as:
[tex]Sin(\theta)=\frac{Opposite}{Hyotenuse}[/tex]
Where [tex]\theta[/tex] is the angle (here angle Q)
Opposite side is RS (which is 15)
Hypotenuse is given as QS (which is 17)
So,
[tex]SinQ=\frac{15}{17}[/tex]
This is the value of SinQ.
We don't want the angle, so we'll stop here.
